Embark on a journey to streamline your SBI Clerk exam preparation with Simplification Study Notes enriched with Memory-Based Questions, meticulously crafted by Chanakya's Coaching Centre Chandigarh. Navigating through mathematical complexities becomes seamless as our study materials provide a comprehensive understanding of simplification techniques crucial for the SBI Clerk exam. Chanakya's Coaching Centre Chandigarh commitment to excellence shines through these notes, ensuring a strategic approach to mastering mathematical concepts. Tailored for efficiency, our study resources equip aspirants with the skills needed to tackle the intricacies of simplification, enhancing problem-solving capabilities. Elevate your preparation with Chanakya's Coaching Centre Chandigarh Simplification Study Notes, a vital tool for success in the SBI Clerk exam, and embrace a confident stride towards achieving your career goals. Before starting the theory part, let's understand what kind of questions are asked in Previous Year Papers. <h2 id="content-id-167076-0">Simplification Questions asked in SBI Clerk Exam</h2> E.g. 88.88% of 243 + 75% of 80 + 14.28% of 56 = ? [SBI Clerk 2022] Sol. 88.88% of 243 + 75% of 80 + 14.28% of 56 = ? Applying the BODMAS rule ⇒ 8 × 11.11% × 243 + 75% × 80 + 14.28% × 56 = ? ⇒ 8 × (1/9) × 243 + (3/4) × 80 + (1/7) × 56 = ? ⇒ 8 × 27 + 3 × 20 + 8 = ? ⇒ 216 + 60 + 8 = ? ⇒ ? = 284 E.g. (17.28 ÷ 0.12) ÷ 3.6 × 0.2 = ? [SBI Clerk 2021] Sol. (17.28 ÷ 0.12) ÷ 3.6 × 0.2 = ? Applying the BODMAS rule ⇒ (144) ÷ 3.6 × 0.2 = ? ⇒ 40 × 0.2 = ? ⇒ ? = 8 E.g. 40% of 475 + 190% of 600 + 1 = ?3 [SBI Clerk 2020] Sol. 40% of 475 + 190% of 600 + 1 = ?3 Applying the BODMAS rule ⇒ (2/5) × 475 + (19/10) × 600 + 1 = ?3 ⇒ 2 × 95 + 19 × 60 + 1 = ?3 ⇒ 190 + 1140 + 1 = ?3 ⇒ ?3 = 1331 ⇒ ? = 11 (Ans.) So, these type of questions are asked in the Exam. So, we will focus on this topic and try to cover all the important aspects of this topic. <h2 id="content-id-167076-1">Simplification Concept Understanding</h2> Here, we are going to learn all about the BODMAS rule, what it is, where to use it along with some mind-blowing formulae which will transform you into human calculator. E.g. 76 + 72 × 442 ÷ 26 = ? We are completely clueless about where to start right now, so let’s start from right ⇒ 76 + 49 × 442 ÷ 26 = ? ⇒ 125 × 442 ÷ 26 = ? ⇒ 55250 ÷ 26 = ? ⇒ ? = 2125 Which is wrong, so how to approach these types of questions? Is there a specific method to approach them? Yes, BODMAS rule. <h3>BODMAS Rule:</h3> Full form of BODMAS is B - Bracket, O - Of, D - Divide, M - Multiply, A - Addition, S - Substraction For every question we have to do each step from up to bottom. Let’s now take previous example and try to solve it. 76 + 72 × 442 ÷ 26 = ? ⇒ 76 + 49 × 442 ÷ 26 = ? Divide: ⇒ 76 + 49 × 17 = ? Multiply: ⇒ 76 + 833 = ? Add: ⇒ ? = 909 (Ans.) Let's take some examples to understand this better. E.g. 27 – [162 – (273 + 281) ÷ 2] = ? Sol. Using the BODMAS rule: ⇒ 27 – [256 – 554/2] = ? ⇒ 27 – 256 + 277 = ? ⇒ ? = 48 (Ans.) E.g. 4.5 + 23.50 + 14.58 – 17.68 × 0.5 = ? Sol. Using the BODMAS rule: ⇒ 4.5 + 23.50 + 14.58 – 8.84 = ? ⇒ 42.58 – 8.84 = ? ⇒ ? = 33.74 (Ans.) E.g. 14 × 627 ÷ √1089 = (?)3 + 141 Sol. 14 × 627 ÷ √1089 = (?)3 + 141 Using the BODMAS rule: ⇒ 14 × 627 ÷ 33 = (?)3 + 141 ⇒ 14 × 19 = (?)3 + 141 ⇒ 266 = (?)3 + 141 ⇒ 125 = (?)3 ⇒ ? = 5 (Ans.) Now, let's understand tips to solve Simplification Questions in Exam. <h2 id="content-id-167076-2">Tips to Solve Simplification Questions</h2> Here are some tips to help you solve simplification questions: General Tips: <ul> <li>Read the question carefully: Make sure you understand what the question is asking for before you start solving.</li> <li>Identify the order of operations: Remember BODMAS (which we have discussed above).</li> <li>Simplify terms one at a time: Don't try to simplify everything at once. Break down the problem into smaller parts and simplify each part one at a time.</li> <li>Look for patterns: See if you can identify any patterns in the problem that can help you simplify it.</li> <li>Use estimation: If you're stuck, try estimating the answer. This can give you a good starting point and help you check your work.</li> </ul> Specific Tips: <ul> <li>Fractions: Simplify fractions by finding the greatest common factor (GCD) of the numerator and denominator.</li> <li>Decimals: Use a place value chart to help you line up the decimals correctly.</li> <li>Percentages: Remember that a percentage is a fraction out of 100.</li> <li>Powers and exponents: Use the rules of exponents to simplify expressions with powers.</li> <li>Negative numbers: Be careful when working with negative numbers. Remember that two negatives make a positive.</li> <li>Brackets: Simplify expressions inside brackets before you simplify the rest of the expression.</li> </ul> (We will discuss all these specific tips in detail in our next study blog) Practice: The best way to improve your skills at solving simplification questions is to practice. There are many resources available online and in textbooks that can help you practice. Directions (Q. 1 - 50): What value should come in the place of question mark (?) in the following questions? 1) 124 % of 3250 + (3/8) of 5712 = (?)2 + 243 a) 83 b) 73 c) 77 d) 87 e) None of these 2) ? % of 600 = 3285 - (442 – 192 ) × 19 ÷ 399 a) 535 b) 610 c) 475 d) 650 e) None of these 3) 72 × 6 × (125 - 97) + 1254 ÷ 3 ÷ 11 – 662 =? a) 6152 b) 6524 c) 7196 d) 7778 e) None of these 4) ∛13824 + ∛74088 % of 250 - ∛3375 % of 600 =? a) 15 b) 9 c) 21 d) 18 e) None of these 5) (5/17) of (408/55) of (165/240) of 6000 = 25 % of ? a) 36000 b) 32000 c) 45000 d) 41000 e) None of these 6) √[(1573 ÷ 13) × (275 ÷ 55) + 53 - 1] = 1672 ÷ 11 - ? 3 a) 8 b) 6 c) 5 d) 7 e) None of these 7) 8 4/7 + 9 ¾ - 3 5/8 - ? = 6 29/56 a) 8 5/28 b) 6 13/25 c) 7 19/28 d) 5 3/4 e) None of these 8) (422 – 182 ) × 24 ÷ 128 + ? % of 1800 = 1080 a) 60 b) 75 c) 45 d) 50 e) None of these 9) (7 × 7)4 ÷ (343 ÷ 7)2 × (343 × 7)3 = (7)? + 5 a) 11 b) 9 c) 13 d) 7 e) None of these 10) 114 % of 1250 + (4/7) of 5712 = (?)2 + 65 a) 84 b) 96 c) 72 d) 68 e) None of these By following these tips and practicing regularly, you'll be able to solve simplification questions with confidence. We will discuss this simplification topic in detail in our next study note with some more examples and some other small topics in simplification like Surds and Indices. Till then, stay tuned! Chanakya's Coaching Centre is widely recognized as the best bank coaching in Chandigarh, offering top-notch guidance for aspirants preparing for exams like IBPS, SBI, RBI, and other competitive banking exams. With a team of experienced faculty, result-oriented strategies, and comprehensive study material, Chanakya’s ensures that students receive the best training to crack their exams with confidence. The institute’s consistent track record of selections, personalized attention, and a disciplined learning environment make it the first choice for serious banking aspirants in Chandigarh. Whether you're starting your preparation or aiming to improve your score, Chanakya’s Coaching Centre is the trusted name to shape your banking career.

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